posted by Jennifer .
A .20 kg ball is attached to a vertical spring. The spring constant is 28 N/m. The ball is supported initially so that the spring is neither stretched or compressed, is released from rest. How far does the ball fall before brought to a momentary stop by the spring?
Our teacher gave us a hint:
But I think that there is something missing, perhaps subscripts (initial and final). And if that's the case, then, I'll get PE=PE.
Also, someone else in class explained that PE=mgh and solved the problem, but I do not know how she got .5 for h.
Please help, so confused. Thank you.
ETi = ETf
Ek+ Eg+Ee = Ek+Eg+Ee
since vi and vf is o Ek is taken out, and having a ref point at the bottom Eg is for ETf is taken out( final hight =0 meters). Also spring is at equilibirum in the beinging, so Ee for ETi is also taken out( xi = O meters)
so then Eg= Ee
and mghi= 0.5(k)(xf)^2
ur hi= xf
wats weird is my gr.12 physics teacher gave the same exact question, kk hope it helped! good luck