PreCalc

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Write the following expression as one logarithm: 2logx-log4-log3+logx.

• PreCalc -
• PreCalc -

That does not seem right to me because when i graph it, they turn out different.

• PreCalc -

I am using the 3 major laws of logs

logA + logB = log(AB)
logA - logB = log(A/B)
nlogA = log (A^n)

so again...

2logx-log4-log3+logx
= log(x^2) -log4-log3 + logx
= log((x^2)(x)/((3)(4))
= log (x^3/12)

You must be graphing it incorrrectly.

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