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Using the binomial theorem, Find the first three terms in the expansion of (x-(1/x))^5.

My solution:
C(5,0)x5 + C(5,1)(x4)(-1/x) + C(5,2)(x3)(-1/x)2
x5 + (5)(x4)(-1/x) + 10(x3)(-1/x)2
x5 + (-5x4/x) + 10(x3)(1/x2)
x5 + (-5x3) + 10(x)
x5 -5x3 + 10x

The first three terms are x5, -5x3, and 10x, respectably.

Is this right? Thanks a lot.

  • Math -

    I agree.

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