MATH!! probability
posted by chris .
Two cards are drawn without replacement from a deck of 52 cards.
Determine P(A and B) where
A : the first card is a spade
B: the second card is a face card
please help!!

Since a tutor hasn't answer I'll try
A. 1st is a spade
P = S/N
Number of spades in deck = 13 = S
Number of cards = 52 = N
P = S/N = 13/52 = 1/4
B. 2nd is a face card
P = S/N
Number of face cards in deck = 13 = S
Number of cards = 52  1 = 51 = N
P = S/N = 13/51
P = P(A) * P(B)
P = 1/4 * 13/51 = 13/204
Not a tutor but I think it is correct
maybe a tutor will answer 
number of spades = 13
number of face cards = 12
number of face OR faces = 21
P(A and B) = P(A) + P(b)  P(A or B)
= 13/52 + 12/52  21/52 = 4/52 = 1/13 
Number of Spades in deck=1/13