I am a three-digit decimal number.My thousandths is twice my tenths.What number am I?
To solve this problem, let's break down the information given:
1. You are a three-digit decimal number.
This means that the number is in the form of A.BC, where A, B, and C represent digits.
2. Your thousandths is twice your tenths.
The thousandths digit is the digit after the decimal point and the tenths digit is the digit right before the decimal point.
Let's use algebra to represent the number: A.BC
According to the information given:
C = 2B
Now, let's explore the possible values for A, B, and C.
Since A, B, and C are digits, they can take values from 0 to 9.
Let's consider the values of B.
If B = 0, then C = 0. But since C must be twice B, this doesn't satisfy the condition.
If B = 1, then C = 2. This means the number is A.12
If B = 2, then C = 4. This means the number is A.24
If B = 3, then C = 6. This means the number is A.36
If B = 4, then C = 8. This means the number is A.48
If B = 5, then C = 10. Since C cannot be greater than 9, this is not valid.
If B = 6, then C = 12. Since C cannot be greater than 9, this is not valid.
If B = 7, then C = 14. Since C cannot be greater than 9, this is not valid.
If B = 8, then C = 16. Since C cannot be greater than 9, this is not valid.
If B = 9, then C = 18. Since C cannot be greater than 9, this is not valid.
From the valid cases, we can see that the possible numbers are A.12, A.24, A.36, and A.48.
Since A is not given, we cannot determine the exact number. However, the possible numbers that satisfy the given conditions are:
- 0.12, 0.24, 0.36, 0.48
- 1.12, 1.24, 1.36, 1.48
- 2.12, 2.24, 2.36, 2.48
- ...
- 9.12, 9.24, 9.36, 9.48
So, the number could be any of these possibilities.