in 1992, the life expectancy of males in a certain country was 67.5 years. In 1997, it was 69.9 years. let E represent the life expectancy in years t and let t represent the number os years since 1992. The linear function E(t) that fits the data is
slope = m = (69.9 - 67.5) / (97-92)
e = m t + 67.5
slope is (69.9-67.5)/5
E= slope*t+67.5
thank you
To find the linear function E(t) that fits the data, we can use the formula for the equation of a line, y = mx + b, where y represents the dependent variable (life expectancy), x represents the independent variable (years since 1992), m represents the slope of the line, and b represents the y-intercept.
Let's start by finding the slope, m. We can use the formula: m = (y₂ - y₁) / (x₂ - x₁), where (x₁, y₁) and (x₂, y₂) are the coordinates of two points on the line.
In this case, (x₁, y₁) = (0, 67.5) and (x₂, y₂) = (5, 69.9).
m = (69.9 - 67.5) / (5 - 0)
m = 2.4 / 5
m = 0.48
Now we can find the y-intercept, b, by substituting the values of one of the points and the slope into the equation y = mx + b. Let's use the point (0, 67.5) for simplicity.
67.5 = (0.48)(0) + b
67.5 = b
So, the y-intercept, b, is 67.5.
Putting it all together, the linear function E(t) that fits the data is:
E(t) = 0.48t + 67.5