If you start with ten grams of lithium hydroxide, how many grams of lithium bromide will be produced? Round to the nearest tenth. Don't forget the units.
Here is a solved example of a stoichiometry problem. Just follow the steps. Post your work if you get stuck.
http://www.jiskha.com/science/chemistry/stoichiometry.html
208,8 g
To determine the number of grams of lithium bromide produced, we need to know the balanced chemical equation for the reaction between lithium hydroxide (LiOH) and lithium bromide (LiBr). Without this information, it is not possible to directly calculate the exact amount of lithium bromide produced.
However, assuming a balanced chemical equation is given, we can use stoichiometry to solve the problem. Let's say the balanced equation is as follows:
2 LiOH + LiBr -> Li2O + LiBr + H2O
According to the balanced equation, it takes 2 moles of LiOH to produce 1 mole of LiBr.
First, convert the given mass of lithium hydroxide (10 grams) to moles by using its molar mass. The molar mass of LiOH is 23.95 g/mol for lithium, 16.00 g/mol for oxygen, and 1.01 g/mol for hydrogen, giving a total of 40.96 g/mol for LiOH. Thus, 10 grams of LiOH is equal to 0.244 moles (10 g / 40.96 g/mol).
Next, using the stoichiometry from the balanced equation, we can calculate the number of moles of LiBr produced. Since it takes 2 moles of LiOH to produce 1 mole of LiBr, we divide the moles of LiOH by the stoichiometric ratio:
0.244 moles LiOH * (1 mole LiBr / 2 moles LiOH) = 0.122 moles LiBr
Finally, multiply the molar mass of LiBr (86.85 g/mol) by the number of moles to find the mass of LiBr produced:
0.122 moles LiBr * 86.85 g/mol = 10.6 grams LiBr
Rounded to the nearest tenth, approximately 10.6 grams of lithium bromide will be produced.