Chemistry

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A .35M solution of a newly synthesized acid, HX, has [H+] of 4.1 x 10^-2. What is the value of Ka for this acid?

  • Chemistry -

    ...............HX ==> H^+ + X^-
    initial.....(0.35M)..(0)....(0)
    change........ -x.....x......x
    final.......(0.35-x)..x......x

    Ka = (H^+)(X^-)/(HX)
    The problem tells you that x (H^+) = 4.1E-2. Substitute into the Ka expression above and solve for Ka.

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