using the balanced equation for the fermentation reaction, calculate for the theoretical amount of alcohol to be produced using 10 grams of sucrose. 0.79 g/ml is ethanol's density.
sorry there is slight changes. Here is the correct answer
10grams of sucrose ÷ 180.15768g/mol sucrose × 2mol ethanol × 46.06904g/mol ethanol ÷ 0.79g/mL
= 6.5 mL ethanol
Here is a worked example of a stoichiometry problem. Just follow the steps. Post your work if you get stuck.
http://www.jiskha.com/science/chemistry/stoichiometry.html
10grams of sucrose ÷ 180.15768g/mol sucrose × 2mol ethanol × 6.06904g/mol ethanol ÷ 0.79g/mL
= 6.5 mL ethanol
To calculate the theoretical amount of alcohol produced from 10 grams of sucrose, we first need to determine the number of moles of sucrose. Here's how you can do it:
Step 1: Find the molar mass of sucrose.
Sucrose, also known as table sugar, has the chemical formula C12H22O11. You can find the atomic masses from the periodic table.
C: 12.01 g/mol
H: 1.01 g/mol
O: 16.00 g/mol
Now, calculate the molar mass of sucrose by adding up the atomic masses:
(12.01 * 12) + (1.01 * 22) + (16.00 * 11) = 342.34 g/mol
So, the molar mass of sucrose is 342.34 g/mol.
Step 2: Convert grams of sucrose to moles.
Use the formula: Moles = mass / molar mass
Moles of sucrose = 10 g / 342.34 g/mol ≈ 0.0292 mol of sucrose
Step 3: Determine the stoichiometry between sucrose and ethanol.
The balanced equation for fermentation of sucrose is:
C12H22O11 + H2O → 4C2H5OH + 4CO2
From the equation, you can see that 1 mole of sucrose produces 4 moles of ethanol.
Step 4: Calculate the theoretical amount of ethanol.
Multiply the moles of sucrose by the stoichiometric ratio:
0.0292 mol of sucrose x (4 mol of ethanol / 1 mol of sucrose) = 0.1168 mol of ethanol
Step 5: Convert moles of ethanol to grams.
Since you have the density of ethanol, you can convert moles to grams using the formula:
Grams = moles x molar mass
The molar mass of ethanol (C2H5OH) is:
(12.01 * 2) + (1.01 * 6) + (16.00 + 1) = 46.07 g/mol
Grams of ethanol = 0.1168 mol x 46.07 g/mol ≈ 5.38 g of ethanol
So, the theoretical amount of alcohol to be produced from 10 grams of sucrose is approximately 5.38 grams.