Convert 50.4 grams of calcium bromide to molecules?
1 mole of CaBr2 (199.9 grams--the molar mass) will contain 6.022E23 molecules. So how many molecules will be in 50.4 g of CaBr2?
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To convert grams of a substance to molecules, we need to use the concept of molar mass and Avogadro's number.
1. Find the molar mass of calcium bromide (CaBr2). The molar mass of calcium (Ca) is 40.08 g/mol, and the molar mass of bromine (Br) is 79.90 g/mol. Since there are two bromine atoms in calcium bromide, we multiply the molar mass of bromine by 2.
Molar mass of CaBr2 = (40.08 g/mol) + (79.90 g/mol × 2) = 40.08 g/mol + 159.80 g/mol = 199.88 g/mol
2. Use the molar mass to convert grams to moles. We divide the given mass by the molar mass.
Moles of CaBr2 = 50.4 g / 199.88 g/mol ≈ 0.252 moles
3. Finally, use Avogadro's number to convert moles to molecules. Avogadro's number is approximately 6.022 × 10^23 molecules per mole.
Molecules of CaBr2 = 0.252 moles × (6.022 × 10^23 molecules/mole) ≈ 1.520 × 10^23 molecules
Therefore, 50.4 grams of calcium bromide is approximately equal to 1.520 × 10^23 molecules.
To convert grams of a substance to molecules, we need to use the concept of moles and Avogadro's number. Here's how you can do it:
Step 1: Determine the molar mass of calcium bromide (CaBr2).
The molar mass of calcium (Ca) is approximately 40.08 g/mol, and the molar mass of bromine (Br) is approximately 79.90 g/mol. Calcium bromide consists of one calcium atom and two bromine atoms, so the molar mass of calcium bromide can be calculated as follows:
Molar mass of CaBr2 = (Molar mass of Ca) + 2 × (Molar mass of Br) = 40.08 g/mol + 2 × 79.90 g/mol = 199.88 g/mol
Step 2: Convert grams to moles.
Using the formula:
Number of moles = Mass (in grams) / Molar mass (in grams per mole)
For calcium bromide (CaBr2):
Number of moles = 50.4 g / 199.88 g/mol ≈ 0.252 moles
Step 3: Convert moles to molecules.
To convert from moles to molecules, we use Avogadro's number, which is approximately 6.022 × 10^23 molecules per mole.
Number of molecules = Number of moles × Avogadro's number
Number of molecules = 0.252 moles × 6.022 × 10^23 molecules per mole ≈ 1.52 × 10^23 molecules
Therefore, 50.4 grams of calcium bromide is approximately equal to 1.52 × 10^23 molecules.