# algebra

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5/4x+1/8x=5/8+x

• algebra -

do you mean
(5/4)x
or
5/(4x) etc

• algebra -

5/4x+1/8x=5/8+x

10/8x + 1/8x = 5/8 + x
11/8x = 5/8 + x
11/8x + x = 5/8
19/8x = 5/8
x = (5/8) / (19/8)
x = (5/8)* (8/19)
x = 40/152 = 5/19

• algebra -

Asuming the problem to be
5/4x + 1/8x = 5/8 + x

(10 + 1) / 8x = (5 + 8x) / 8

ie. 11/ 8x = (8x + 5) / 8

11 = 8x (8x +5) / 8

ie. 11 = 8x ^2 + 5x

We will now have to handle it as a quadratic equation:

8x ^2 + 5x - 11 = 0

Apply the formula to get the roots:

(-b + Sqrt ( b^2 - 4ac) ) / 2a
-

Hope this clarifies enough!

• algebra -

If you meant
5/(4x) + 1/(8x) = 5/(8+x) then follow Kay's solution

if you meant it the way you typed it, the follow Ms. Sue's way, except I noted an error in her 3rd line, should have been ....
11/8x - x = 5/8
3/8x = 5/8
x = (5/8) / (3/8)
x = (5/8)* (8/3)
x = 40/152 = 5/3

• algebra -

Oops! Thanks for the correction, Reiny.

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