find 10-7 divided by 10-7 to determine how much more intense earthquake A was than earthquake B 10-7 DIVIDED BY 10-3
To find out how much more intense earthquake A was than earthquake B, we need to calculate the ratio of their magnitudes.
The expression you provided, 10-7 divided by 10-7, can be simplified to 1 divided by 1. Any number divided by itself is always 1. Therefore, the result is 1.
However, it seems there was a typo in the second part of your question. You wrote "10-3" instead of "10-7". Let's assume you want to find the ratio between 10-7 divided by 10-7 and 10-7 divided by 10-3.
To calculate this, we can divide the first ratio by the second ratio:
(10-7 ÷ 10-7) ÷ (10-7 ÷ 10-3)
Now, let's simplify the expression step by step:
First, 10-7 ÷ 10-7 equals 1.
Next, we have:
1 ÷ (10-7 ÷ 10-3)
To divide by a fraction, we multiply by its reciprocal:
1 × (10-3 ÷ 10-7)
Now, let's simplify by subtracting the exponents:
1 × 10(3-(-7))
Simplifying further:
1 × 10(3+7) = 1 × 1010 = 10^10
Therefore, earthquake A was 10^10 times more intense than earthquake B.