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Mathematics
Algebra
Sequences
the sum of the first 2 terms of a geometric sequence is 3. the sum of the next 2 terms is 4/3. find the 4 terms of the sequence.
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Look at the method used in the first of "Related questions" below. Apply the same method here.
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1. Find the sum of the first five terms of the sequence 2/3, 2, 6, 18, .....
2. Is this a geometric sequence? 2x, (4x-2), (6x-4),
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1. looks like a GS, were a = 2/3, and r = 3 sum(5) = a(r^5 - 1)/(r-1) = (2/3)(3^5 -1)/2 = ..... 2.
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Use the geometric sequence of numbers 1, 1/3, 1/9, 1/27… to find the following:
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S10 =a(r^n -1)/r-1 S10=? r=⅓÷1=⅓ a=1 n=10 By substitution, S10=1(⅓^10-1)/⅓-1 S10 =
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Use the geometric sequence of numbers 1, 1/3, 1/9 , 1/27… to find the following:
b) Using the formula for the sum of the first
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Lol that's easy but I'm late to the question on pour pose I've just been too busy
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sum of 2nd and 5th terms of a geometric sequence is 13. the sum of the 3rd and 6th is -39.
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The sequence is or the form a(1 + r + r^2 + ...) The first term is a1 = a The second term is a2 =a*r
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as with any geometric sequence, Sn = a(1-r^n)/(1-r) So, since a=x and r=x, Sn = x(1-x^n)/(1-x) 1b) S
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The sum of the first three terms of a geometric sequence is 49/ 32 and the sum of the next three terms is 49/ 256 . Find the
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a(1-r^3)/(1-r) = 49/32 a(1-r^6)/(1-r) - 40/32 = 49/256 a(1-r^3)/(1-r) = 49/32 a(1-r^6)/(1-r) =
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My answer is 12276, is this correct?
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1)The sum of 6 terms of an arithmetic series is 45, the sum of 12 terms is -8. Find the first term and the common difference?
2)I
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You have to know the formula for the sum of n terms of an AS Sum(6) = 3(2a + 5d) 6a + 15d = 45 ---
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The sum of the 2nd and 5th terms of a geometric sequence is 3.5. The sum of the 3rd and 6th is -7. Determine the ratio r of the
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ar + ar^4 = 7/2 ar^2 + ar^5 = -7 divide and you have r(1+r^3) / r^2(1+r^3) = -1/2 1/r = -1/2 r = -2
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5. In a geometric sequence, the sum of the first five terms is 44 and the sum of the next five terms is -11/8. Find the common
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S5 = a(1-r^5)/(1-r) = 44 S10 = a(1-r^10)/(1-r) = 44 - 11/8 now divide (1-r^10)/(1-r^5) = (44 -
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