beth has $0.60 more than suzy. together they have $8.20. how much money does each girl have?

Let x = the amount that Suzy has.

x + x + 0.60 = 8.20

2x = 8.20 - 0.60
2x = 7.60

x = 3.80

if the teacher have to send a kid named sean every day to the principal how much does he go there for one year and how much times does he stay there for?

To find out how much money each girl has, we can set up a system of equations based on the information given.

Let's assume the amount of money Suzy has is 'x' dollars. According to the problem, Beth has $0.60 more than Suzy, so the amount of money Beth has would be 'x + $0.60'.

The problem also states that together they have $8.20, so we can write an equation based on that information:

x + (x + $0.60) = $8.20

Simplifying the equation, we get:

2x + $0.60 = $8.20

Subtracting $0.60 from both sides of the equation, we have:

2x = $7.60

Dividing both sides by 2, we find:

x = $3.80

So, Suzy has $3.80.

To find how much money Beth has, we can substitute the value of x into one of the equations, since we know Beth has $0.60 more than Suzy:

x + $0.60 = $3.80 + $0.60 = $4.40

Therefore, Beth has $4.40.

Let x be the amount of money Beth has. Let y be the amount of money Suzy has.

"beth has $0.60 more than suzy."
x = 0.60+y.

"together they have $8.20."
x+y = 8.20

Solve the system of equations.

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