what is the probability of selecting two s's in the word massachusetts if the s is replaced before the second

To determine the probability of selecting two "S"s in the word "Massachusetts" when the "S" is replaced before the second selection, we need to consider the number of "S"s in the word and the total number of letters.

First, let's count the number of "S"s in the word "Massachusetts." We have 2 "S"s in total.

Next, we need to determine the total number of letters in the word "Massachusetts." The word consists of 13 letters in total.

Now, since the "S" is replaced before the second selection, the probability of selecting an "S" on both draws is the same as the probability of selecting an "S" on a single draw.

Therefore, the probability of selecting an "S" is calculated by dividing the number of "S"s by the total number of letters:

Probability = Number of "S"s / Total number of letters
Probability = 2 / 13

So, the probability of selecting two "S"s in the word "Massachusetts" when the "S" is replaced before the second selection is 2/13.

There are 13 letters and 4 s's.

P = 4/13 for each s.

The probability of both/all events occurring is found by multiplying the the probabilities of the individual events.