Simon and Jimmy had 167 stamps

altogether. Simon gave 4/7 of his stamps to Trina, and Jimmy gave 37 stamps to Trina. Simon and Jimmy had the same number of stamps left. How many stamps did Jimmy have in the beginning?

Please Help ME:
I need a formula

10 answers

let the number of stamps that Simon has be x

then the number of stamps that Jimmy has be 167-x

Simon gives 4/7 of his to Trina, so he has (3/7)x left
Jimmy gives 37 to Trina, so he has 167-x - 37 or 130-x left

but now they have the same

solve : (3/7)x = 130 - x
hint: multiply both sides by 7 etc.

Simon has 91, but Jimmy had 76

Simon started with 91 and Jimmy started with 76. Trina has 89 when it is done.

Simon and Jimmy had 167 stamps

let the number of stamps that Simon has be x

Simon has 91, but Jimmy had 76

Simon started with 91 and Jimmy started with 76. Trina has 89 when it is done.

I checked and got 91 btw

Check your work it is 91

91 for Simon in the BEGINNING and 76 for jimmy in the beggining

Pretty sure it's 76.

76

I HAVE A QUESTION, IS IT 72 or 76, pls make sure it is correct and use a caculator if you must.

72