Determine the mass of phosphoric acid that can be produced by the reaction of 1 ton of phosphate rock, Ca(PO4)2, and sulfuric acid.

this will help you write the chemical equation-

double replacement reaction:
(Broken Link Removed)

find the limiting reagent:
http://www.chem.tamu.edu/class/majors/tutorialnotefiles/limiting.htm

be sure to convert the 1 ton to grams!

To determine the mass of phosphoric acid produced by the reaction of 1 ton of phosphate rock (Ca(PO4)2) and sulfuric acid (H2SO4), we need to use stoichiometry.

Step 1: Write the balanced chemical equation for the reaction:
Ca(PO4)2 + 3H2SO4 -> 2H3PO4 + CaSO4

This equation tells us that 1 mole of Ca(PO4)2 reacts with 3 moles of H2SO4 to produce 2 moles of H3PO4 and 1 mole of CaSO4.

Step 2: Calculate the molar mass of Ca(PO4)2:
Ca = 40.08 g/mol
P = 30.97 g/mol
O = 16.00 g/mol

Molar mass of Ca(PO4)2 = (40.08 g/mol * 1) + (30.97 g/mol * 2) + (16.00 g/mol * 8) = 310.18 g/mol

Step 3: Convert 1 ton of Ca(PO4)2 to grams:
1 ton = 1000 kg = 1000000 g

Step 4: Calculate the number of moles of Ca(PO4)2:
Number of moles = mass (g) / molar mass (g/mol)
Number of moles = 1000000 g / 310.18 g/mol = 3223.99 mol (approximately)

Step 5: Apply stoichiometry to calculate the moles of H3PO4 produced:
From the balanced equation, we know that 1 mole of Ca(PO4)2 reacts with 2 moles of H3PO4.

Moles of H3PO4 = 3223.99 mol * (2 mol H3PO4 / 1 mol Ca(PO4)2) = 6447.98 mol (approximately)

Step 6: Calculate the mass of H3PO4:
Molar mass of H3PO4 = (1.01 g/mol * 3) + (16.00 g/mol * 1) + (1.01 g/mol * 4) = 98.00 g/mol

Mass of H3PO4 = moles of H3PO4 * molar mass of H3PO4
Mass of H3PO4 = 6447.98 mol * 98.00 g/mol = 631,165.5 g (approximately)

Therefore, approximately 631,165.5 grams (or 631.17 kg) of phosphoric acid can be produced from the reaction of 1 ton of phosphate rock and sulfuric acid.