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algebra

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can someone please help me.

The perimeter of a rectangle is 80m. The length is 7m more than twice and width. Find the dimensions.

I would appreciate help with the steps so I can practice it for the my next problem. Thanks.

  • algebra -

    Let l be the length.
    Let w be the width.

    "The length is 7m more than twice and width."
    l = 2w+7

    The perimeter of a rectangle is P=2(l+w).
    Substitute in l=2w+7 for the length.

    80 = 2(2w+7+w)
    80 = 2(3w+7)
    80 = 6w + 14
    66 = 6w
    w = 11

    l = 2w+7
    l = 29

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