What do you get when you solve this equation where t = time in hours

log t = (0.576 log (72/526) -0.176

Would it matter if t were in minutes?

Thank you

You have two left parentheses and one right so it is not clear what you mean.

Do you mean log base 10?

If t is defined as time in hours in the equation, and you have time in minutes, you need to convert to hours first.

logt = (0.576log(72/526)) - 0.176.

logt = 0.576log(0.136882129) - 0.176,
logt = -0.86365- 0.176,
logt = -1.039653,
10^(-1.039653) = t,
0.091274 = t.

Or t = 0.091274.

The results would be the same regardless of what you call t.

If the problem states that t is in
minutes. Then your answer is in minutes. You can convert to what units
you desire.

To solve the equation log t = (0.576 log (72/526) − 0.176, you can follow these steps:

Step 1: Simplify the right side of the equation by using logarithmic properties:
log (72/526) = log 72 - log 526

Step 2: Calculate the logarithms using base 10:
log 72 ≈ 1.857
log 526 ≈ 2.721

Step 3: Substitute the values back into the equation:
log t = (0.576 * (1.857 - 2.721)) - 0.176

Step 4: Simplify the right side:
log t ≈ (0.576 * (-0.864)) - 0.176
log t ≈ -0.498 - 0.176
log t ≈ -0.674

Step 5: Remove the logarithm using exponentiation:
t ≈ 10^(-0.674)
t ≈ 0.207 hours

Now, let's address whether it matters if t is in minutes instead of hours:

Since the equation log t = (0.576 log (72/526) - 0.176 is based on time in hours, if you change t to represent time in minutes, you would need to adjust the equation accordingly. In this case, you would need to use the conversion factor of 1 hour = 60 minutes.

If you have t represented in minutes, you would need to divide it by 60 to convert it to hours before substituting it into the equation. Once you have the solution in hours, you can convert it back to minutes if needed for your specific situation.