how many moles of water are contained in 0.250 mile of CuSO4 * 5H2O? please help me
0.250 mole CuSO4.5H2O x (5 moles H2O/1 mole CuSO4.5H2O) = ?? moles H2O.
thanks
To determine the number of moles of water in 0.250 mole of CuSO4 * 5H2O, we need to find the molar mass of CuSO4 * 5H2O and then calculate the number of moles.
The molar mass of CuSO4 * 5H2O can be calculated by summing the atomic masses of all the atoms in the compound.
Atomic masses:
Cu (Copper) = 63.55 g/mol
S (Sulfur) = 32.06 g/mol
O (Oxygen) = 16.00 g/mol
H (Hydrogen) = 1.01 g/mol
Now, let's calculate the molar mass of CuSO4 * 5H2O:
CuSO4: (1 * Cu) + (1 * S) + (4 * O) = 63.55 + 32.06 + (4 * 16.00) = 159.61 g/mol
5H2O: (5 * (2 * H)) + (5 * O) = (5 * (2 * 1.01)) + (5 * 16.00) = 90.10 g/mol
Therefore, the molar mass of CuSO4 * 5H2O is:
Molar mass of CuSO4 * 5H2O = 159.61 + 90.10 = 249.71 g/mol
Now, using the given amount of CuSO4 * 5H2O (0.250 mole), we can calculate the moles of water:
Moles of water = (moles of CuSO4 * 5H2O) * (moles of water per mole of CuSO4 * 5H2O)
Moles of water = 0.250 mole * (5 moles of H2O / 1 mole of CuSO4 * 5H2O)
Moles of water = 0.250 mole * 5 = 1.25 mole
Therefore, there are 1.25 moles of water in 0.250 mole of CuSO4 * 5H2O.
To calculate the number of moles of water in 0.250 moles of CuSO4 * 5H2O, you need to know the molar mass of CuSO4 * 5H2O and the molar mass of water.
First, calculate the molar mass of CuSO4*5H2O:
- The molar mass of CuSO4 is 63.55 g/mol for copper (Cu), 32.07 g/mol for sulfur (S), and 16.00 g/mol for oxygen (O). So, (63.55 g/mol + 32.07 g/mol + 4 * 16.00 g/mol) = 159.61 g/mol for CuSO4.
- The molar mass of water (H2O) is 2 * 1.01 g/mol for hydrogen (H) and 16.00 g/mol for oxygen (O). So, (2 * 1.01 g/mol + 16.00 g/mol) = 18.02 g/mol for water.
Now, determine the number of moles of water in 0.250 moles of CuSO4 * 5H2O:
- Multiply the molar mass of water by the number of water molecules in CuSO4 * 5H2O. Since there are 5 water molecules in CuSO4 * 5H2O, multiply the molar mass of water (18.02 g/mol) by 5 to get: (18.02 g/mol * 5) = 90.1 g/mol.
- Next, divide the mass of water in 0.250 moles of CuSO4 * 5H2O by the molar mass of water. So, (0.250 moles * 90.1 g/mol) = 22.525 g of water.
Therefore, 0.250 moles of CuSO4 * 5H2O contains 22.525 grams of water.