Math
posted by Patrice
The factors of x^3 4x^2 x+4 are?
How do I solve this?

Reiny
use grouping
x^2(x4) 1(x4)
= ....
take it from there. 
Patrice
I do not understand how you grouped the numbers?

Reiny
expand my answer,
will you not get the original?
so, can I not reverse the process?
btw, my next step would be
(x4)(x^2  4)
= (x4)(x+1)(x1) 
Henry
x^3 4x^2 x + 4.
The expression has 4 terms. Therefore,
we can form 2 groups with 2 factorable terms in each group:
(x^3  x) + (4x^2 + 4),
Factor each pair:
x(x^2  1) 4(x^2  1),
Factor out (x^2  1):
(x^2  1)(x  4),
(x + 1)(x  1)(x  4).
NOTE: (X^2  1) = (x + 1)(x  1)
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