What is the molar mass of Mg(NO3)2? Explain how you calculated this value.
Molar mass is g/mole
therefor get each elements mass and add the masses together to get molar mass
MgN2O6
http://www.ehow.com/how_4505969_calculate-molar-mass.html
To calculate the molar mass of Mg(NO3)2, we need to determine the atomic masses of all the elements present in the compound and then add them up.
1. Look up the atomic masses of the elements:
- Mg (Magnesium) has an atomic mass of 24.305 grams/mol.
- N (Nitrogen) has an atomic mass of 14.007 grams/mol.
- O (Oxygen) has an atomic mass of 16.00 grams/mol.
2. Determine the number of atoms of each element:
In Mg(NO3)2, there is one magnesium atom (Mg), two nitrate ions (NO3-). Each nitrate ion contains one nitrogen atom and three oxygen atoms.
3. Calculate the molar mass:
- Magnesium (Mg) contributes 1 x 24.305 = 24.305 grams/mol.
- Nitrogen (N) contributes 1 x 14.007 = 14.007 grams/mol.
- Oxygen (O) contributes 2 x (3 x 16.00) = 96.00 grams/mol. (There are three oxygen atoms in each nitrate ion, and we have two nitrate ions.)
Finally, add up the contributions:
Molar mass = 24.305 + 14.007 + 96.00 = 134.312 grams/mol.
So, the molar mass of Mg(NO3)2 is 134.312 grams/mol.