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A sinusoidal transverse wave of amplitude ym = 6.4 cm and wavelength = 5.2 cm travels on a stretched cord. Find the ratio of the maximum particle speed (the speed with which a single particle in the cord moves transverse to the wave) to the wave speed.

  • physics -

    I assume you have had calculus

    y=Asinwt
    where A is 6.4cm
    f=wavespeed/lambda

    w=2PIf=2PIwavspeed/lambda

    y=Asinwt
    y'=particle speed=Awcoswt=A2PI (wavespeed)/lambda

    the maximum occurs at coswt=1
    solve for particle speed/wavespeed.

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