I have no idea how to solve this problem. Can someone help me???

3x+3y=-6(this is a negative 6)
7x+4y= 1

3x+3y=-6

3y=-6-3x Divide with 3
y=-2-x

7x+4y=1
7x+4*(-2-x)=1
7x-8-4x=1
3x-8=1
3x=1+8
3x=9 Divide with 3
x=9/3
x=3

y=-2-x
y=-2-3
y=-5

x=3 y=-5

Cheking of results:
3x+3y=3*3+3*(-5)=9-15=-6

7x+4y=7*3+4*(-5)=21-20=1

which is a table of value for y=x-12

Sure! I can help you solve this system of linear equations. There are a couple of different methods you can use to solve it, but I'll explain the substitution method.

Here's how you can solve it step by step:

1. Start with the given equations:
3x + 3y = -6 --> Equation 1
7x + 4y = 1 --> Equation 2

2. Solve Equation 1 for one variable in terms of the other. In this case, let's solve for x:
3x = -6 - 3y
Divide both sides of the equation by 3:
x = (-6 - 3y) / 3
Simplify:
x = -2 - y --> Equation 3

3. Substitute the expression for x from Equation 3 into Equation 2:
7(-2 - y) + 4y = 1
Simplify:
-14 - 7y + 4y = 1
Combine like terms:
-3y - 14 = 1
Add 14 to both sides of the equation:
-3y = 15
Divide both sides of the equation by -3:
y = -5

4. Substitute the value of y into Equation 3 to find x:
x = -2 - (-5)
Simplify:
x = -2 + 5
x = 3

So the solution to the system of equations is x = 3 and y = -5.

To check your solution, substitute these values back into the original equations and see if they make both equations true.