# math question 4- very urgent !

posted by .

Find the average value of f(x) = x^3 + 3 for 0 ≤ x ≤ 2 and find all values of x* described in the Mean Value
Theorem for Integrals.

## Similar Questions

1. ### math - very urgent !

Verify that f(x) = x^3 − 2x + 6 satisfies the hypothesis of the Mean-Value Theorem over the interval [-2, 3] and find all values of C that satisfy the conclusion of the theorem.
2. ### Math

Minimize C=7x+3y+4z 0≤x 0≤y 0≤z 100≤2x+3y+3z 120≤5x+2z Answer: Minimum value of C =?
3. ### Calculus 3

Compute the average value of following fuction over the region R?
4. ### calculus

A particle moves on the x-axis so that its velocity at any time t is given by v(t) = sin 2t. At t = 0, the particle is at the origin. a)For 0 ≤ t ≤ π, find all values of t for which the particle is moving to the left. …
5. ### algebra 1 help please

4) a student score is 83 and 91 on her first two quizzes. write and solve a compound inequality to find possible values for a thord quiz score that would give anverage between 85 and 90. a. 85≤83+91+n/3 ≤90; 81≤n≤96 …
6. ### Maths

Let f be a function such that f(−6)=−6, f(6)=6, f is differentiable for all real values of x and −1≤f'x≤1 for all real values of x. Prove that f(x)=x for all −6≤x≤6 I tried applying the …
7. ### Calculus

Let f be a function such that f(−6)=−6, f(6)=6, f is differentiable for all real values of x and −1≤f'x≤1 for all real values of x. Prove that f(x)=x for all −6≤x≤6 I tried applying the …
8. ### PRE - CALCULUS

Eliminate the parameter t. Find a rectangular equation for the plane curve defined by the parametric equations. x = 6 cos t, y = 6 sin t; 0 ≤ t ≤ 2π A. x2 - y2 = 6; -6 ≤ x ≤ 6 B. x2 - y2 = 36; -6 ≤ …
9. ### Calculus AB

If f(x) = |(x^2 - 6)(x^2 + 2)|, how many numbers in the interval 1 ≤ x ≤ 2 satisfy the conclusion of the mean value theorem?
10. ### Calculus

Find all the values of a and b in such a way that f is continuous function on its domain. f(x)= { (√x+a)+1 if -a ≤x ≤ 0 2x^2+3 if 0 ≤ x ≤ 1 (x+b)^2+1 if x>1

More Similar Questions