# physics

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a body is projected at an angle with the horizontal with an initial of 500 m/s. 4 seconds later it hits the ground. find theta and the horizontal range.

• physics -

tan theta = Vi/u
sin theta = Vi/500

do the vertical problem first

v = Vi - 9.8 t
let's use the time to top (half the trip)
0 = Vi - 9.8 (2 seconds)
Vi = 19.6 m/s

sin theta = 19.6/500

now you can do the rest I think

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