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a body is projected at an angle with the horizontal with an initial of 500 m/s. 4 seconds later it hits the ground. find theta and the horizontal range.

  • physics -

    tan theta = Vi/u
    sin theta = Vi/500

    do the vertical problem first

    v = Vi - 9.8 t
    let's use the time to top (half the trip)
    0 = Vi - 9.8 (2 seconds)
    Vi = 19.6 m/s

    sin theta = 19.6/500

    now you can do the rest I think

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