How many ions are in 0.585 mol of manganese (IV) chloride?
MnCl4.
There are 6.022E23 molecules of MnCl4 in 1 mole; therefore, in 0.585 moles there will be 0.585 x 6.022E23 individual molecules. There are 5 ions in 1 molecule (1 Mn ion and 4 Cl ions) so five times that number will be the total number of ions.