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posted by john Sunday, December 19, 2010 at 2:04pm.

Find the average value of f (x)= √(4x +1) over the interval 0 ≤ x ≤ 2.

(1/2) int (4x+1)^.5 dx from 0 to 2 (1/2) [(2/(3*4))(4x+1)^1.5] at 2 - at 1 (1/12) [ (27) - (11.2) ] 1.32

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