calculus  Integration
posted by Geoff .
evaluate
∫sec^7 x tanx dx

calculus  Integration 
Damon
let u = sec x
then du = sec x tan x dx
so then we have
u^6 du
u^7/7
(1/7)sec^7 x + c
Respond to this Question
Similar Questions

Integration?
Use the derivatives of sinx and cosx to show that d/dx [tanx] = sec^2 and that d/dx [secx]=sec^2xsinx. Hence evaluate ∫ [1 + sinx]/[cos^2x] dx limit from 0 to pi I know the first part of the question, i'm not sure how i should … 
Integration?
Sorry, i have a load of questions on integration... thanks for any help provided! Evaluate the integrals: limit 0 to pi/4 ∫ [sec^2x]/[5+tanx] dx limit 0 to pi/6 ∫ [3cos3x]/[3+sin3x] dx limit 0 to 3 ∫ [2x1]/[x^2x+1] … 
calculus  Integration
Evaluate ∫ [(5+x)^2]/√x 
Calculus
Evaluate the indefinite integral. ∫ sec^3x tanx dx I let u=tanx took derivative.. du=sec^2x dx ..now what? 
calculus
Did I do this problem right? Find the first and second derativesimplify your answer. y=xtanx y'= (x)(sec^2 x)+(tanx)(1) y'= xsec^2 x + tanx y"= (x)(2secx)(secxtanx)+sec^2 x + sec^2 x y"=2xsec^2 x tanx + 2 sec^2 x 
Help Evaluating Integrals
1.) ∫ (2)/(x4) dx 2.) ∫ sec^2x tanx dx 3.) ∫ 2 csc^2 xdx 4.) ∫ (3) / sqtr(x+3) dx 5.) ∫ (2x1) / (x^2  x) 
Calculus
I'm having trouble reversing the order of integration of ∫∫dxdy from a=0 to b=2(3)^(1/2) for x and c=y^(2/6) to d=(16y^2)^(1/2) for y. I graphed the region of integration and that still doesn't really help me. i got approximately … 
Calculus. I need help!
Evaluate the indefinite integral (a.)∫√(cotx)csc^2xdx (b.)∫sec^3xtanxdx 
calculus (check my work please)
Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)1) dx ∫ tan(x)sec(x)[sec^4(x)sec^2(x)] … 
Calculus AP
I'm doing trigonometric integrals i wanted to know im doing step is my answer right?