A 70 kg man weighs 686 N on the Earth's surface. How far above the surface of the Earth would he have to go to "lose" 14% of his body weight?
someone pleaaaase answer my question! i have no clue how to do it!
its quite difficult.
i also hvn't any idea how to do it.
Is your answer 100 root 28672/6
To calculate how far above the surface of the Earth the man would have to go to "lose" 14% of his body weight, we need to consider the relationship between weight, mass, and distance from the Earth's surface.
First, let's find the weight lost by the man. We can calculate this by multiplying his weight by 14%:
Weight lost = 14% of 686 N = 0.14 * 686 = 96.04 N
Weight is directly proportional to the acceleration due to gravity (9.8 m/s²) and inversely proportional to the square of the distance from the center of the Earth. We can use this relationship to find the distance from the Earth's surface.
Let's define the weight at the new distance (d meters above the surface) as W. The man's weight at the Earth's surface (W0) is 686 N.
Using the formula for weight, we can write:
W = (W0 / d²) * (R + d)²
Where R is the radius of the Earth (approximately 6,371 km) and d is the distance from the Earth's surface.
Now, we can solve for d. Rearranging the equation, we get:
d² = ((W0 / W) * (R + d)²) - R²
Substituting the values we know, we have:
d² = ((686 N / 96.04 N) * (6,371 km + d)²) - (6,371 km)²
Simplifying the equation gives us a quadratic equation. To solve it, let's plug in the values into a numerical solver or use trial and error to find the value of d. However, since the quadratic equation is complicated and does not have a simple solution, it may be easier to use numerical methods or approximation techniques instead.
Therefore, to accurately calculate the distance above the Earth's surface where the man would lose 14% of his body weight, it would be best to use numerical methods or approximation techniques.