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Given the position function s = 4t^3 − 24t^2 + 6t + 6.

find s and v when a = 0

(Where v is the velocity and a is the acceleration.).

  • math -

    v= ds/dt=12t^2-48t+6
    a= dv/dt=24t-48=0 so t=2

    find s, v when t=2

  • math -

    so i just have to sub t=2 in
    v = 12t^2-48t+6 to get v and
    s = 4t^3-24t^2+6t+6 to get s ?

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