3/2(4x-6)-x(3-x)=1/3x(3x-6)

I assume you that you need to solve for x?

3/2(4x-6)-x(3-x)=1/3x(3x-6)

multiply through by 2 and by 3 to remove the fractions

9(4x-6)-6x(3-x)=2x(3x-6)

remove the brackets

36x-54-18x+6x^2=6x^2-12x

36x-54-18x=-12x

group like terms

18x-54=-12x

30x=54

hence find x

Check my algebra!