the solution to the system of equations y= 2x and y = -x + 3 is
a)2,1
b)(-1,2)
c)2,-1)
d)(1,2)
y=-x^2+3 and y=2x
To find the solution to the system of equations y = 2x and y = -x + 3, we need to solve the equations simultaneously.
Step 1: Set the two equations equal to each other:
2x = -x + 3
Step 2: Add x to both sides of the equation:
2x + x = -x + x + 3
3x = 3
Step 3: Divide both sides of the equation by 3:
3x/3 = 3/3
x = 1
Step 4: Substitute the value of x into one of the equations to find the value of y. Let's use the first equation:
y = 2x
y = 2(1)
y = 2
Therefore, the solution to the system of equations is (1, 2), which corresponds to option (d).
To find the solution to the system of equations y = 2x and y = -x + 3, we need to solve both equations simultaneously.
First, we notice that both equations are already solved for y.
Setting the expressions for y equal to each other, we have:
2x = -x + 3
Now we can solve for x by combining like terms:
2x + x = 3
3x = 3
Divide both sides by 3:
x = 1
Now that we have found the value of x, we can substitute it back into either equation to find the corresponding y-value. Let's use the first equation y = 2x:
y = 2(1)
y = 2
Therefore, the solution to the system of equations is (1, 2).
The answer is (d) (1, 2).
D.
to solve for x:
Since y= 2x you would plug in the 2x where the y is making it 2x=-x +3.
Then add an x to both sides to get all the x's on one side of the equation. So it would then look like
3x=3. Divide both sides by 3 to get the x alone and you now have x=1
then to solve for y you plug the x value in where the x's are. y=-1+3. Solve, and y= 2.
Therefore the answer is D(1,2)