What is the slope of the line described by the equation 1

_____________________________-x+-y=5___
________________________________3______ i hope someone understands this problem

ugh sorry it looks rediculous. let me try again -x+1/3y=5

solve for y. Slope is the coefficent of the x term when the equation is in the form

y=mx+b

To find the slope of the line described by the equation, you need to rewrite the equation in slope-intercept form, which is in the form of y = mx + b, where m is the slope.

Given equation: -(1/3)x - y = 5

First, you'll rearrange the equation to solve for y:
-y = (1/3)x + 5

Next, divide both sides by -1 to isolate y:
y = -(1/3)x - 5

Now that the equation is in slope-intercept form, you can easily see that the slope (m) is -1/3. The numerator -1 represents the change in y, while the denominator 3 represents the change in x. So, for every 3 units increase in x, the corresponding y-value decreases by 1 unit.

Therefore, the slope of the line is -1/3.