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A projectile fired vertically up from a cannon rises 200 m before returning to the ground. If the same cannon were to fire the same projectile at an angle 45 degrees, then the maximum range would be m.

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    When fired straight up, the height attained is
    H = V^2/(2g)

    When fired at at angle A, the range is
    R = (V^2/g)sin(2A)

    When the angle is 45 degrees, R = V^2/g
    and R = 2 H. (The H refers to the straight-up value)

    Therefore the answer is 400 m.

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