a gas has a pressure of 1.1 atm occupies a volume of 24 liters. What will the pressure be if the gas has a final volume of 19 liters at constant temperature?

P1V1 = P2V2

To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.

Boyle's Law is expressed as P1V1 = P2V2, where P1 and V1 represent the initial pressure and volume, and P2 and V2 represent the final pressure and volume.

Given:
Initial pressure (P1) = 1.1 atm
Initial volume (V1) = 24 liters
Final volume (V2) = 19 liters

We need to find the final pressure (P2).

Using Boyle's Law, we can rewrite the equation as:

P1V1 = P2V2

Substituting the given values:

(1.1 atm) (24 L) = P2 (19 L)

Now we can solve for P2:

P2 = (1.1 atm) (24 L) / (19 L)

P2 = 1.386 atm

Therefore, the final pressure of the gas will be approximately 1.386 atm when the volume is reduced to 19 liters at a constant temperature.