An athlete whirls a 7.00 kg hammer tied to the end of a 1.1 m chain in a horizontal circle. The hammer makes one revolution in 0.9 s. What is the tension in the chain?
396 (approx)
396 N (approx)
A single electron is placed in an electric field where the intensity 103.5 N/c. What force does the electron experience?
To find the tension in the chain, we can use the centripetal force formula. The centripetal force is the force that keeps an object moving in a circular path. In this case, the tension in the chain provides the centripetal force to keep the hammer moving in a circle.
The centripetal force formula is given by:
F = (m * v^2) / r
Where:
F is the centripetal force
m is the mass of the object (7.00 kg)
v is the velocity of the object (which can be calculated using the formula v = 2πr / T)
r is the radius of the circular path (1.1 m)
T is the time it takes for one revolution (0.9 s)
First, let's calculate the velocity using the formula v = 2πr / T:
v = (2 * π * 1.1 m) / 0.9 s
v ≈ 7.75 m/s
Now, substitute the values into the centripetal force formula:
F = (7.00 kg * (7.75 m/s)^2) / 1.1 m
F ≈ 385.7 N
Therefore, the tension in the chain is approximately 385.7 N.
The speed of the hammer must be
V = 2 pi*1.1/0.9 = 7.68 m/s. The chain cannot not be quite horizontal, but tipped at an angle A (to support the weight) so that
M V^2/R = T cos A and
M g = T sin A
tan A = g R/V^2 = 0.183
which means that
A = 10.3 degrees
T = (M V^2/R)/cos10.3 = ______
If you do not include the cos 10.5 factor, your answer will be about 2% off.