posted by Anonymous .
A person fishing hooks a 3.0-kg fish on a line that can only sustain a maximum of 35 N of force before breaking. At one point while reeling in the bass, it fights back with a force of 45 N. What is the minimum acceleration with which you must play out the line during this time in order to keep the line from breaking?
If the fish does actually exert a force of 45 N on the line, it will break. It exerts its force mainly on the water around it, away from the fisherman. If it accelerates backwards in the process due to released line, a line at its breaking point exerts a force on the fish (and vice versa) equal to 45 N - Ma = 35 N. The backwards acceleration of the fish is then
a = 10 N/g = 1.02 m/s^2