11th grade
posted by Leonardo Figueroa .
You push a 250 kg desk with a force of 800N. The coefficient of friction is 0.2. What is the acceleration of the desk?

Remember the equation: deltaF = ma
In this case delta F is the force applied(800N)Force of friction.
Now we need to find out the force of friction(Ff). We can do this through the equation Ff=uN.
u is given(.2)
N(the normal force)opposes the downward force of the desk(mg)250*9.81.
Thus Ff=.2*250*9.81=490.5
Back to the original equation, deltaF=ma. now all we do is plug in the values and solve for a.
800490.5=250a
309.5/250=a
1.24=a
theres your answer, hope i helped 
Omer is correct. Thanks for helping, Omer