4). At diving competiotion, Jan's first dive received 9 scores that averaged 9.0. To calculate her final score for the dive, the highest and lowest scores were removed and the average was taken of the remaining seven scores. If her final score was 9.1, what was the sum of the teo removed scores?

to get an average of 9 on 9 scores, her total of all the scores must have been 81

So after the high and low are removed there were 7 scores for an average of 9.1
so that total must have been 9.1(7) = 63.7

so the sum of the two scores removes was 17.3

To find the sum of the two removed scores, we need to know the average of the seven remaining scores. Let's assume the average of the seven remaining scores is "x."

We know that Jan's first dive received 9 scores that averaged 9.0. This means the sum of all nine scores is 9.0 * 9 = 81.

To calculate the sum of the seven remaining scores, we need to multiply the average by the number of scores: 7 * x.

We also know that her final score for the dive was 9.1. Since we removed the highest and lowest scores, the sum of the seven remaining scores should be (7 * x) - (the sum of the two removed scores).

Given that Jan's overall score for the dive was 9.1, we can set up the following equation:

(7 * x) - (sum of two removed scores) = 9.1

Now, let's substitute the values we know:

(7 * x) - (sum of two removed scores) = 9.1
(7 * x) - (81 - sum of two removed scores) = 9.1

Simplifying the equation:

7x - 81 + (sum of two removed scores) = 9.1
7x + (sum of two removed scores) = 90.1

To solve for the sum of the two removed scores, we'll need to know the value of x (the average of the seven remaining scores). Unfortunately, this information is not given in the question, so we cannot answer the question without knowing that value.