posted by Darryl .
In the reaction: MnO2 + 4 HCl ---> MnCl2 + Cl2 + 2 H2O
The volume of Cl2 produced from the reaction of 10 grams of HCl with excess MnO2?
Here is a worked example of a stoichiometric problem. Just follow the steps. After you find moles Cl2, moles x 22.4 L/mol will give you the volume.