A rectangle has a perimeter of 48m. The width is 2m less than the length. Use an equation to find each dimension.
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Maybe this is to figure the size of a jail cell????
P = 2L + 2W
48 = 2L + 2(L - 2)
48 = 4L - 4
52 = 4L
13 = L
An 11 x 13 m room (36 x 43 foot) might be suitable for celebrities in rehab.
Goodness! That's considerably larger than my apartment! :-)
To find the dimensions of the rectangle, we need to use the given information and set up an equation.
Let's assign a variable to one of the dimensions:
Let x be the length of the rectangle in meters.
According to the problem, the width is 2 meters less than the length. Therefore, the width would be x - 2.
The perimeter of a rectangle is equal to the sum of all sides. In this case, the perimeter is 48 meters.
The perimeter of a rectangle is given by the formula:
Perimeter = 2(Length + Width)
We can substitute the given values into the formula:
48 = 2(x + (x - 2))
Now we can solve the equation to find the length:
48 = 2(2x - 2) [Distribute the 2]
48 = 4x - 4 [Simplify]
52 = 4x [Add 4 to both sides]
Divide both sides by 4:
13 = x [Divide both sides by 4]
So the length of the rectangle is 13 meters.
Now we can find the width by substituting the value of x into the expression we found earlier:
Width = Length - 2
Width = 13 - 2
Width = 11 meters
Therefore, the dimensions of the rectangle are 13 meters by 11 meters.