Calculus

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On an 18-hole golf course, there are par-3 holes, par-4 holes and par-5 holes. A golfer shoots a par of 70 for the 18 holes. There are twice as many par-4 holes as par-5 holes. How many of each type of hole are there on the golf course?

  • Calculus -

    number of par 5 ---- x
    number of par 4 ---- 2x
    number of par 3 ---- 18-x-2x = 18-3x

    solve
    5x + 4(2x) + 3(18-3x) = 70
    ..
    .
    x = 4

    par 5 --- 4
    par 4 --- 8
    par 3 --- 6

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