THANK YOU!
Solve by substitution
3x+6y=6;
-6x+y=40
My WORK: Y=40+6X;
3X+6(40+6X)=6; 3X+240+36X=6;
x=-5.51;
y=40+6(-5.51); y=40+-33.06;
y=6.94
(-5.51,6.94)
Is this right???
You have and error.
3X + 240 + 36X = 6
39X = -234
X = ?
my misspelling...
You have AN eror.
OK, I will try this. Please let me know.
39x= -234; Divide by 39 on each side.
x = 6.
y=40+6(-6); 40+-36 = 4; (6,4)?
"39x= -234; Divide by 39 on each side.
x = -6. "
thank you so much!
To solve the system of equations by substitution, you need to solve one equation for one variable and substitute it into the other equation. Let's go through the steps:
1. Start with the original system of equations:
3x + 6y = 6 ...(Equation 1)
-6x + y = 40 ...(Equation 2)
2. Solve Equation 2 for y:
Rearrange Equation 2 to isolate y:
y = 6x + 40
3. Substitute the expression for y from Equation 2 into Equation 1:
Replace y in Equation 1 with (6x + 40):
3x + 6(6x + 40) = 6
4. Simplify and solve for x:
Distribute the 6 to the terms inside the parentheses:
3x + 36x + 240 = 6
Combine like terms:
39x + 240 = 6
Subtract 240 from both sides:
39x = -234
Divide both sides by 39:
x = -6
5. Substitute the found value of x (x = -6) into Equation 2 to find y:
-6(-6) + y = 40
36 + y = 40
Subtract 36 from both sides:
y = 4
Therefore, the solution to the system of equations is x = -6 and y = 4. Your calculated values of x and y (-5.51 and 6.94) do not match the correct solution. Please review your calculations and steps again to resolve any errors.