A girl breathes in a volume of 2 . 6L of air dives to a depth that has a temperature of -11 degrees Celcius What volume of air will she breathe in when she resurfaces to a temperature of 37 C???
I don't understand the question.
hmm me either
ok a swimmer takes a deep breath in.....the volume of air taken into the lungs is 2.6 litres she then dives to a depth where the temperature is -11 degrees Celsius when she is out of air she swims back to the top of the ocean where the temperature is 37 degrees celcius what volume of air does she inhale now? i think we should use the gas law PV=nRT or i was trying to relate Charle's VT law i don't know
To find the volume of air the girl will breathe in when she resurfaces to a temperature of 37°C, we can use Charles's Law. Charles's Law states that the volume of a gas is directly proportional to its temperature, assuming pressure and amount of gas remain constant.
First, let's convert the temperatures from Celsius to Kelvin since Kelvin is the absolute temperature scale. To convert Celsius to Kelvin, we need to add 273.15 to the Celsius temperature.
Given:
Initial volume (V1) = 2.6 L
Initial temperature (T1) = -11°C = 262.15 K
Final temperature (T2) = 37°C = 310.15 K
Next, we can set up a ratio using Charles's Law:
(V1 / T1) = (V2 / T2)
Now, we can plug in the values into the equation:
(2.6 L / 262.15 K) = (V2 / 310.15 K)
To find V2 (the volume of air she will breathe in when resurfacing), we can cross-multiply:
V2 = (2.6 L / 262.15 K) * 310.15 K
V2 ≈ 3.08 L
Therefore, when the girl resurfaces to a temperature of 37°C, she will breathe in approximately 3.08 liters of air.