a 751 diver drops from a board 9.10 m above the water's surface. How much kinetic energy does the diver have right before he hits the water?

Base on the law of conservation of energy, energy cannot be created nor destroyed. Knowing this, potential energy=kinetic energy. Find the potential energy. PE=mgh m=mass, g=gravity, h=height

To calculate the kinetic energy of the diver right before hitting the water, we need to know the mass of the diver and their velocity. The formula for kinetic energy is:

Kinetic Energy = 1/2 * mass * velocity^2

Given that we do not have the mass or velocity of the diver, we can still calculate the velocity using the concept of gravitational potential energy.

Gravitational potential energy is given by the formula:

Potential Energy = mass * gravity * height

Since the diver drops from a height of 9.10 m, we can calculate the potential energy using this formula. The gravitational constant, which measures the strength of gravity, is approximately 9.8 m/s^2.

Potential Energy = mass * 9.8 m/s^2 * 9.10 m

Now, since potential energy is converted into kinetic energy as the diver falls, we can equate the potential energy to the kinetic energy:

Potential Energy = Kinetic Energy

mass * 9.8 m/s^2 * 9.10 m = 1/2 * mass * velocity^2

Simplifying the equation, we can solve for the velocity:

velocity^2 = 2 * 9.8 m/s^2 * 9.10 m

Now, we can calculate the velocity:

velocity = √(2 * 9.8 m/s^2 * 9.10 m)

Finally, with the velocity known, we can substitute it into the formula for kinetic energy to find the answer:

Kinetic Energy = 1/2 * mass * velocity^2

Please provide the mass of the diver to get the exact value of the kinetic energy.