posted by .

Doing some test corrections and not seeing this....Please help:


csc^4x - cot^4x = 2csc^2x-1

  • Precalculus -

    Not a surprise that you don't get it,
    the two expressions are not equivalent!

    Start from left:
    Factor sin^4(x) as denominator:
    Factor as difference of two squares
    = (1 + cos²(x)) (1 - cos²(x)) / sin^4(x)
    =(1 + cos²(x))sin²(x)/sin^4(x)
    (and not 2csc²(x)+1)

  • Precalculus -

    1-csc^4x=2 csc ^2x-csc^4x

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math (trig)

    Prove: sin^2(x/2) = csc^2x - cot^2x / 2csc^2(x) + 2csc(x)cot(x) On the right, factor the numberator as a difference of two perfect squares. In the denominator, factor out 2cscx. You ought to prodeed rather quickly to the proof.
  2. Precalculus

    Having trouble with this: Verify: csc^4x-cot^4x=2csc^2x-1 *the numbers after the carets are to the power of
  3. trig

    verify : [sec(x) / csc(x) - cot(x)] - [sec(x) / csc(x) + cot(x)] = 2csc(x)
  4. trig

    For each expression in column I, choose the expression from column II to complete an identity: Column I Column II 1. -tanxcosx A. sin^2x/cos^2x 2. sec^2x-1 B. 1/sec^2x 3. sec x/cscx C. sin(-x) 4. 1+sin^2x^2x-cot^2x+sin^2x 5. …
  5. Math

    What is the first step. Explain please. Which expression is equivalent to cos^2x + cot^2x + sin2^x?
  6. trig

    verify (csc^4-1)/cot^2x=2+cot^2x So this is what I have so far on the left side (csc^2x+1)(cscx+1)(cscx-1)/cot^2x =(csc^2x+1)(cot^2x)/cot^2x i think I'm doing something wrong. Please help!
  7. trigonometry

    Verify that sec(θ)/csc(θ)-cot(θ) - sec(θ)/csc(θ)-cot(θ) = 2csc(θ) is an identity. can some help me through this?
  8. math

    Verify that sec(θ)/csc(θ)-cot(θ) - sec(θ)/csc(θ)-cot(θ) = 2csc(θ) is an identity. please help! thank you!
  9. Math

    Find an equation for the tangent line to the curve at (π/2 , 2). y = 4 + cot(x) - 2csc(x) I am confused how to take the derivative of this problem. When I tried to solve it I ended up with -csc^2 (x) + (2csc(x) * cot(x)). From …
  10. Pre-Calculus

    Verify the identity. (csc(2x) - sin(2x))/cot(2x)=cos(2x) =csc(2x)/cot(2x) - sin(2x)/cot(2x) =csc(2x)/cot(2x) - cos(2x) Is this correct so far?

More Similar Questions