Bob is riding his bike along at 2m/s and drops his 2kg backpack from a height of 1.5 meters. What is the backpacks resulting velocity when it strikes the ground?

To find the backpack's resulting velocity when it strikes the ground, you can use the principles of physics, specifically the equations of motion. Here's how you can calculate it:

Step 1: Find the time it takes for the backpack to fall from a height of 1.5 meters. You can use the equation:

h = (1/2)gt^2

Where:
h = height (1.5 meters)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken

Rearranging the equation, we get:

t^2 = (2h) / g

Substituting the values, we have:

t^2 = (2 * 1.5) / 9.8
t^2 = 0.3061
t ≈ 0.554 seconds

Step 2: Once you have the time it takes for the backpack to fall, you can use another equation to calculate the final velocity. In this case, you can use the equation:

v = gt

Where:
v = final velocity
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken

Substituting the values, we have:

v = 9.8 * 0.554
v ≈ 5.426 m/s

Therefore, the resulting velocity of the backpack when it strikes the ground is approximately 5.426 m/s.