A plane traveling at 600 mph leaves 3/4 hr earlier than a plane traveling at 800 mph. when will the second plane surpass the first?
Distance = rate * time
600(x+3/4) = 800x
Solve for x.
To determine when the second plane will surpass the first, we need to find the time it takes for the second plane to cover the same distance as the first plane.
Let's assume that the time the second plane travels is represented by "t" hours.
Therefore, the time the first plane travels would be "t + 3/4" hours, since it leaves 3/4 hour earlier.
We can calculate the distance covered by each plane using the formula: distance = speed × time.
For the first plane: distance = 600 mph × (t + 3/4) hr = 600t + 450 miles.
For the second plane: distance = 800 mph × t hr = 800t miles.
Now, we need to find the value of "t" when the second plane surpasses the first. This occurs when the distance covered by the second plane is greater than the distance covered by the first plane.
800t > 600t + 450
To solve for "t":
800t - 600t > 450
200t > 450
t > 450/200
t > 2.25
Therefore, the second plane will surpass the first plane after approximately 2.25 hours.