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Calculate the weight percent of water in NiSO4 6H2O, how to calculate it?
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See your two posts above.
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Calculate the weight percent of water in NiSO4 6H2O, how to calculate it?
Top answer:
see your post above.
Read more.
Calculate the weight percent of water in NiSO4 6H2O, how to calculate it?
Top answer:
To calculate the weight percent of water in NiSO4 · 6H2O, you need the molar mass of water (H2O)
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You need to make a .300 M solution of NiSO4 aq. Calculate the mass of NiSO4 6H2O you should put into a .100-L volumetric flasl
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Top answer:
How many mols do you need? That's mols NiSO4.6H2O = M x L = 0.3M x 0.1 L = ? Then grams = mols x
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need to calculate percent yield of MgNH4PO4 . 6H2O obtained in my experiment using 10-52-10 plant food label as a guide to
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I forgot to add that in my experiment I used 1.2 grams of 10-52-10 plant food ( + 4 grams MgSO4
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You wish to make a 0.200 M solution of NiSO4 (aq). How many grams of NiSO4 * 6H2O should you put in a 0.500 L volumetric flask?
T
Top answer:
Find moles first: That is M x L = 0.20 x 0.500L = ? Then convert from moles to grams with
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you need to make .80 M solution of NiSO4 (aq). How many grams of NiSO4 * 6H2O should you put into a .50 L volumetric flask?
Top answer:
You want how many moles? That is M x L = 0.80 x 0.500L = ? Then grams = moles/molar mass. You want
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How many grams of NiSO4*6H2O are needed to prepare 200*10^2 mL of a 3.5*10^-2 M NiSO4 solution?
Top answer:
How many moles do you need? moles = M x L = ?? Convert that to grams. g = ?? moles x molar mass
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Charges on the metal
MgSO4 = +2 NiSO4*6H2O = +2 CoCl2*6H2O = +2 KCr(SO4)2*12H2O = +3 CuSO4*5H2O = +2 (NH4)2Cr2O7 = +2 FeSO4*7H2O
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I'm not sure if the above answers are correct, could someone please check them over and let me know?
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Find the number of unpaired electrons on the central metal atom of following:
MgSO4 NiSO4.6H2O CoCl2.6H2O KCr(SO4)2.12H2O
Top answer:
I don't think anyone here will do all of these for you. Here are a couple with explanation. MgSO4 is
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what are the charges on the metals?
MgSO4 NiSO4*6H2O CoCl2*6H2O could you just explain how you determined the first one? I can
Top answer:
You can do it one of several ways. 1. Look at the periodic table. Mg is in group II. Mg is +2. 2.
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